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If you’re a serious woodworker, than the DEWALT DW680K planer is a necessary addition to your woodworking shop. The rugged 7 amp, 15,000 rpm motor produces steady, level results on even the toughest applications. This planer features increased function and quality with up to 3/32-inches of cut in a single pass and an increased amount of passes allowed with handy kick stand. The DW680K is compatible with reversible carbide blades that are equipped for resharpening and ideal for straight edge or framings. A precision-machined shoe maintains even results and produces perfectly square rabbet joints and is crafted with three precision machined guides in the front generate three distinct beveling channels. Features include the innovative Calibrated Depth Adjustment Knob to ensure positions are fine-tuned so you never have to re-zero the depth and height adjustment knob, ergonomically set in rubber for increased height command.
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Will a 1.5 V battery (AA) power one yellow 3mm led that needs 1.8 volts to power?
will a 1.5 V battery (AA) power one yellow 3mm led that needs 1.8 volts to power? I had already bought everything to do this. please tell me if it will work. if it wont work is there any way to make it work? please help. thanks.
It will work, but without a resistor in series with the LED the battery will die very quickly. An LED is just a diode that lights up. Putting one across a battery is the same as short circuiting it, will cause the battery to die quickly and may cause the LED to burn out right away. You have to use a resistor in line with it to provide the battery with a load. If you know the current rating of the LED you can figure out what size resistor to use. Divide the voltage by the LED current rating to get the resistor you need. If the LED is rated at 30mA and you intend to run it from a AA battery, divide 1½ by .03 to get a 50 ohm resistor. These are not typical values. Good luck.
Woodstock W1226 Mini-Planer Pal, Pair
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Where can I find out how much current a 3MM copper weir can handle?
I made an electromagnet using five strains of 3mm copper (normally used for winding in a generator) and I need to know how much power I can run on it whiteout destroying it.
Kind of a hard quetsion to answer, but I found this link. Hope this explains what you're looking for Chers http://www.rowand.net/Shop/Tech/WireCapacityChart.htm
A piston is 6.3mm in diameter. assume that a force of 3 tons is 3.0x10(to the fourth power)N?..?
what force must be exerted on the piston to lift the 3 ton weight???
1 Ton = 1000 kg 3 Tons = 3000 kg (mass) Weight = mg = (3000 kg)(10 m/s^2) = 3 x 10^4 Newton Answer: force = 3 x 10^4 N
Estimate the average power the bee expends in hovering. And if you could show the work that would be great!?
A typical bumblebee has mass 0.25mg . It beats its wings 100 times per second, and the wings undergo an average displacement of about 1.3mm . When the bee is hovering over a flower, the average force between wings and air must support the bee's weight
Wing velocity = 100 x 1.3mm = 130mm/s = 0.13m/s P = f v = m g v = 2.5e-4 x 9.8 x 0.13 = 3.2e-4W = 0.32mW
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